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x^2+2x-148.413159=0
a = 1; b = 2; c = -148.413159;
Δ = b2-4ac
Δ = 22-4·1·(-148.413159)
Δ = 597.652636
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{597.652636}}{2*1}=\frac{-2-\sqrt{597.652636}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{597.652636}}{2*1}=\frac{-2+\sqrt{597.652636}}{2} $
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